Mechanics / forces / newton's laws
Motion Does Not Require a Force
That a moving object must have a force acting on it, and that when the force is 'used up' the object stops — the medieval impetus theory, which most students hold walking into their first mechanics class and many still hold walking out.
A force is not what keeps a thing moving. A net force — the sum of every push and pull on an object — changes its velocity: starts it, speeds it up, slows it down. Take every force away and a moving object does not stop. It keeps its velocity, forever. Nothing about that sentence feels true, because you have never lived anywhere it is visibly true.
Your intuition says the opposite: push a box and it moves; stop pushing and it stops. Motion looks like something you have to keep paying for, as if the push were a fuel the object burns through. That theory has a name — impetus — it was mainstream physics for a thousand years, and tests like the Force Concept Inventory show most students still hold it after being taught otherwise. This page is an experiment you can run until the theory breaks in your hands.
The instrument below is a block of mass m on a flat floor, watched for 8 seconds. You choose a push force and how long to apply it, what force (if any) you keep applying afterwards, and how much friction the floor has. Every time you move a control the whole 8 seconds is recomputed from rest. Start by pressing nothing at all: at the default settings — a 2 kg block, friction coefficient 0.25, a 9.8 N push for the first second, nothing after — the verdict line reads stopped at 2.0 s. It moved while you pushed, coasted briefly, and died. Exactly what your intuition predicted. Now let's find out who actually took the speed.
The floor's friction force is μ × m × g with g = 9.8 m/s², opposing motion while the block moves, and matching your push (up to that same maximum) while it stands still. Integrated at 1 ms steps, semi-implicit Euler; for the constant forces used here that is exact to the displayed digits.
friction is draining speed · speed constant or growing · a gap means the block is standing still
Read the log. It never says the block "ran out of push". It says friction — 4.90 N of it, pointing backwards the whole time the block moved — took 2.45 m/s off the velocity every second, and when the velocity reached zero, the block stopped. The speed was not spent. It was removed, by a force, at a rate you can now predict: friction force divided by mass, 4.90 N ÷ 2 kg = 2.45 m/s².
Test that. Push twice as hard — slide the push force to 19.6 N, everything else untouched. The block leaves the push phase at 7.35 m/s and now takes until 4.0 s to die — but watch the slope of the decay: still exactly 2.45 m/s lost per second. A bigger push bought more velocity; it did not change the rate at which the floor collects it. If motion were a fuel, a harder shove would burn slower. It doesn't. The dying rate belongs to the floor, not to the shove.
One more thing your intuition already knows, now with a mechanism under it. Set the push force down to 3.0 N (still 19.6's opposite: a feeble shove). The block never moves — the verdict reads never moves — and the log shows why: static friction answers your 3.0 N with exactly 3.0 N back, net force 0.00 N. Friction is not a fixed toll. Below its maximum of 4.90 N it is a mirror, matching whatever you apply.
Your intuition is right — about a world with friction in it
Here is the experiment that shows why the impetus theory feels so solid. Set the push force back to 9.8 N and, this time, keep a force on after the push: set the after-force to 4.9 N — precisely the kinetic friction. The block leaves the push at 2.45 m/s and then cruises at a constant 2.45 m/s for the remaining seven seconds, covering 18.38 m in total. The verdict reads cruising at a constant 2.45 m/s.
So yes: on this floor, keeping the block moving costs a steady 4.9 N. Your daily experience is correct. But look at the net-force line in the log: your 4.9 N forward plus friction's 4.90 N backward is 0.00 N. The force you supply is not sustaining the motion. It is cancelling friction, so that nothing at all acts on the block — and with nothing acting, velocity stays what it is. Constant velocity is not the signature of a maintained force. It is the signature of forces that sum to zero.
The proof: nudge the after-force up to 9.8 N, more than friction. If force sustained speed, more force should mean a higher constant speed. Instead the block never settles: it is still speeding up when the clock runs out, passing 19.60 m/s at t = 8 s and gaining 2.45 m/s every second, without limit. A steady unbalanced force does not set a speed. It sets a rate of change of speed: a = F ÷ m.
Now remove the floor's opinion
Everything so far had friction in it — the ingredient your intuition was trained on. Take it out. Set μ to 0 and the after-force back to 0, keeping the 9.8 N, 1-second push. With no friction the whole push goes into speed — a = 9.8 N ÷ 2 kg, so the block exits the push at 4.90 m/s — and then, with no push and no friction, nothing touches it. The chart goes flat and stays flat: constant at 4.90 m/s with nothing acting on it, still doing 4.90 m/s when the clock ends, 36.75 m down the track. Run it for eight seconds or eight years; the answer is the same.
That flat line is Newton's first law: an object keeps a constant velocity unless a net force acts on it. It is not a special behaviour that needs explaining. It is the default, and it was in front of you all along — hidden under a floor that never stopped acting. The reason nobody believes the first law from a lecture is that Earth supplies friction and drag with everything, so the "default" state is literally unobservable in daily life. You have to pay for smooth ice or an air table — or leave the atmosphere — to see it. That is also why an orbiting astronaut's wrench floats alongside her — and here gravity very much still acts, nearly as strongly as on the ground. Gravity is the only force on the astronaut and the only force on the wrench, so it accelerates both along the same curve at the same rate. Relative to her, the wrench feels no leftover force at all — the μ = 0 condition of this experiment — so it stays exactly where she let go of it.
Last experiment, the strangest one. Keep μ at 0 and set the after-force to just 2.0 N — a fingertip. On the friction floor, 2.0 N couldn't even start the block. Here, with nothing to cancel it, that fingertip accelerates the block forever: 1.00 m/s gained every second, 11.90 m/s by the end of the window, any speed you like if you wait. This is how a spacecraft's small thruster reaches enormous speeds: not by being strong, but by being unopposed.
Seeing it on Earth
You cannot switch friction off in your kitchen, but you can shrink it and watch the impetus theory fail by degrees. Roll a ball at the same starting speed across carpet, wood and smooth ice: if speed were a fuel the ball carries, the surface wouldn't matter — same ball, same "push", it should die at the same rate everywhere. Instead the dying rate tracks the surface, exactly as the μ slider does above. An air-hockey puck is the μ ≈ 0 row of this experiment: between hits, its speed is as close to constant as anything you will ever touch. And when the ball on ice finally does stop, you now know what to write down: not "it ran out", but "a backward force of μmg acted for v ÷ (μg) seconds".
Where this goes next: once "force changes motion" replaces "force maintains motion", two more traps are waiting. The first is gravity — whether a heavier object falls faster (it pulls harder, and yet it doesn't). The second is the crash on the highway: whether the truck hits the car harder than the car hits the truck. It doesn't either, and the reason is this page's a = F ÷ m applied twice.
A puck slides on frictionless ice at 5 m/s. To keep it moving at a steady 5 m/s, the force you must apply is…